a. 300 m/s b. East A. Momentum= mv Divide both sides by m to get: v= "Momentum"/m Substitute what they gave you into that formula now v= (2.40*10^3) /8 v= 3*10^2 v=300 (unless I did this …

Angular momentum =9.375kg cdot m^2s^-1 Angular velocity=1.5radcdot s^-1 For any object which is rotating about an axis, each point located on the object has the same angular velocity …

4.3ms^-1 and 75.9J Conservation of momentum states that before and after a physical reaction there must always be the same amount of momentum. Momentum is the product of mass and …

The formula for force applied on an object is F=ma, where F equals force applied, m equals mass and a equals acceleration. Since the car and the truck are moving at with the same …

The speed of hero's hand is about 1.08 times greater than the bullet speed. To solve this, use the law of momentum conservation. Suppose two obejects A (=m_1) and B (=m_2) have a …

The angular momentum, #I#, for a solid disk is given by #I = (M*r^2)/2# #I = (6 kg* (5 m)^2)/2 = 75 kg*m^2# Going back to the formula for torque, #tau = 75 kg*m^2*8.4 (radians)/s^2 = 630 …

A ball with a mass of #2 kg# is rolling at #9 m/s# and elastically collides with a resting ball with a mass of #1 kg#. What are the post-collision velocities of the balls? PhysicsMomentum and …

How does momentum differ from inertia? What is the molecular geometry of BCl3? Draw its VSEPR and Lewis structure. How can I draw the Lewis dot structure for BeF2? What is a …

The ratio between the final and initial momentum will give us the fractional increase in momentum. #P_f/P_i = sqrt (2m*2K_i)/sqrt (2m*K_i) = sqrt (2) ~= 1.414# The final momentum will be equal …

The total momentum before the collision, 54 kg ms^-1, will be the same as the total momentum after it. When divided by the mass of the second ball this yields a velocity of 13.5 ms^-1. …