
Graphs of logarithmic functions (video) | Khan Academy
The graph of y=log base 2 of x looks like a curve that increases at an ever-decreasing rate as x gets larger. It becomes very negative as x approaches 0 from the right. The graph of y=-log …
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Learn about graphing logarithmic functions through transformations with Khan Academy's step-by-step video tutorial.
Exponential & logarithmic functions | Algebra (all content) | Khan …
This topic covers: - Radicals & rational exponents - Graphs & end behavior of exponential functions - Manipulating exponential expressions using exponent properties - Exponential …
Intro to Logarithms (article) - Khan Academy
Learn about the properties of logarithms that help us rewrite logarithmic expressions, and about the change of base rule that allows us to evaluate any logarithm we want using the calculator.
Graphs of logarithmic functions (practice) | Khan Academy
The graph of y = log 2 x is shown below. Which of the following is the graph of y = 3 log 2 (x 4) ?
Relationship between exponentials & logarithms: graphs
Given a few points on the graph of an exponential function, Sal plots the corresponding points on the graph of the corresponding logarithmic function. Created by Sal Khan.
Logarithms | Algebra 2 | Math | Khan Academy
Logarithms are the inverses of exponents. They allow us to solve challenging exponential equations, and they are a good excuse to dive deeper into the relationship between a function …
Shape of a logarithmic parent graph (video) | Khan Academy
We're asked to graph, y is equal to log base 5 of x. And just to remind us what this is saying, this is saying that y is equal to the power that I have to raise 5 to to get to x.
Intro to logarithms (video) - Khan Academy
Sal explains what logarithms are and gives a few examples of finding logarithms.
Solving exponential equations using logarithms - Khan Academy
Learn how to solve any exponential equation of the form a⋅b^ (cx)=d. For example, solve 6⋅10^ (2x)=48. The key to solving exponential equations lies in logarithms! Let's take a closer look by …