Vertical asymptote is 6 End behaviour (horizontal asymptote) is 5 Y intercept is -7/2 X intercept is 27/5 We know that the normal rational function looks like 1/x What we have to know about this …

How do you find the vertex and the intercepts for g(x) = x2 + 2x − 3? Algebra Quadratic Equations and Functions Vertex Form of a Quadratic Equation

Remove the x from − 10 8 x and move the squaring to outside the brackets y = 4(x − 10 8)2 −6 This will not produce the original equation ddddddddddddddddd as we have not includes a …

Graph opens down. Vertex at (0,-1);Axis of Symmetry: x=0 y = -x^2-1 y is a quadratic function of the from: ax^2+bx+c Where: a=-1, b=0 and c=-1 Since y is a quadratic its graph will be a …

Explanation: One way to find the vertex is to convert the given equation into an explicit vertex form #color (white) ("XXX")y= (x-color (red)a)^2+color (blue) (b)# with vertex at #color (red)a,color …

x intercept: (4/3,0) y intercept: (0,-4) The x intercept is the point of the line for which y=0, so 0=3x-4 -> 3x=4 -> x=4/3 The y intercept is the point of the line for which x=0, so y=3*0-4 = -4

Vertex is (1,1) and intercept on y-axis is 3. There is no intercept on x-axis. Writing the equation y=2x^2-4x+3 in vertex form we have y=2(x^2-2x+1-1)+3 or y=2((x-1)^2)+3-2 or y=2(x-1)^2+1 …

Explanation: The original equation can be transformed to a quadratic equation by a substitution: x2 = t 2t2 − 7t + 6 = 0 Δ = (− 7)2 − 4 ⋅ 2 ⋅ 6 = 49 −48 = 1 √Δ = 1 t1 = 7 − 1 4 = 3 2 and t2 = 7 …

Explanation: You get the x intercept when y=0, i.e. 2x+4=0. This gives x=-2 y intercept is when x = 0, i.e. y=4 Answer link

Oct 29, 2015 · The y-intercept is the value of y when x = 0 (or, it is the value of y where the line crosses the Y-axis and for all points on the Y-axis, x = 0) XXXy = − 3(0) +6 = 6 Similarly, the x …