Therefore since the trig equation we are solving is sin ... we need to use the rule in the 2nd quadrant. From the graph of the function, we can see that we should be expecting 2 solutions: 1 ...

This circle has the centre at the origin and a radius of 1 unit. The point P can move around the circumference of the circle. At point P the \(x\)-coordinate is \(\cos{\theta}\) and the \(y ...